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3 years ago

What is the value of the function at x = 3? Enter your answer in the box.

Mathematics

1 answer:

butalik [34]3 years ago

3 0

Answer:

Step-by-step explanation:

Recall a linear function, is a line on a graph made up of an infinite amount of points which satisfy the relationship. That means at x=3 there is a specific point on the line with an output. The value of a function at x=3 asks, what is the output y value for the input x value?

To find it, we locate 3 on the x-axis. We draw a vertical line directly to the line following the grid line. We mark the point on the line. We then draw a horizontal line directly to the y-axis following the grid line. The point we hit on the y-axis is the value of the function.

Here it is 4.

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Twenty-five less two times a number, x, is fifteen.

Karo-lina-s [1.5K]

Answer:

x=20

Step-by-step explanation:

2x-25=15

2x=40

x=20

8 0

3 years ago

An automobile travels past the farmhouse at a speed of v = 45 km/h. How fast is the distance between the automobile and the farm

yulyashka [42]

Answer:

$\frac{ds}{dt} = 39.586 km/h$

Step-by-step explanation:

let distance between farmhouse and road is 2 km

From diagram given

p is the distance between road and past the intersection of highway

By using Pythagoras theorem

$s^2 = 2^2 +p^2$

differentiate wrt t

we get

$\frac{d}{dt} s^2 = \frac{d}{dt} (4 + p^2)$

$2s \frac{ds}{dt} =2p \frac{dp}{dt}$

$\frac{ds}{dt} = \frac{p}{s}\frac{dp}{dt}$

$\frac{ds}{dt} = \frac{p}{\sqrt{p^2 +4}} \frac{dp}{dt}$

putting p = 3.7 km

$\frac{ds}{dt} = \frac{3.7}{\sqrt{3.7^2 +4}} 45$

$\frac{ds}{dt} = 39.586 km/h$

3 0

3 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

4 0

3 years ago

Braden's employers covers 70% of the cost of a $5100-per-year health insurance plan, and Braden's share of the cost of the plan

borishaifa [10]

I don't know how to get the answer, but i know the answer is 127.50.

5 0

3 years ago

Read 2 more answers

What is the density of a 60-gram pyramid with rectangular base 5 cm x 7 cm and height 9 cm?

JulijaS [17]

Answer:

0.571428571429 grams per cm³

Step-by-step explanation:

density = mass/volume

Let’s calculate the volume V of the pyramid :

V = (1/3)×base×height

= (1÷3)×(5×7)×9

= 105 cm³

Then

The density = mass/volume

= 60÷105

= 0.571428571429

4 0

2 years ago