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Sedaia [141]
3 years ago
14

Find the length of BW

Mathematics
1 answer:
alekssr [168]3 years ago
8 0

Answer:

BW \approx 132.589

Step-by-step explanation:

The given triangle (BWS) is a right triangle. This is indicated by the box around one of its angles, signifying that it is a right angle. One property of a right triangle is the right angle trigonometric ratios. These are a set of ratios that can be used to describe the relationship between the sides and angles in a triangle. These ratios are as follows:

sin(\theta) = \frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

Please note that the (opposite) and (adjacent) sides are subjective, the sides that are named these terms depend on the angle of reference. However the term (hypotenuse) refers to the sides opposite the right angle of a right triangle, this term is the same no matter the angle used in the ratio.

In this case, one is given the length of the side (SB) and the measure of angle (<W), one is asked to find the length of the side (BW). The best ratio to use in this case is the ratio tangent (tan).

tan(\theta)=\frac{opposite}{adjacent}

Substitute,

tan(9)=\frac{21}{adjacent}

Inverse operations,

tan(9)=\frac{21}{adjacent}

adjacent=\frac{21}{(tan(9))}

adjacent\approx132.688782

BW \approx 132.589

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Which of these expressions can be used to calculate the monthly payment for
Masja [62]

Answer:

m=(r/n)+0.114r

Step-by-step explanation:

m=monthly payment

r=remaining amount

n=# of months remaining

7 0
3 years ago
72
Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

OR

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

OR

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

8 0
3 years ago
Please help with this algebra problem!! thanks
saw5 [17]

5.7t < 420  divide both sides by 5.7

5.7      5.7  

t < 73.68

5 0
4 years ago
Read 2 more answers
Need some help please <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B15%7D%20%20%2B%20%28%20-%20%20%5Cfrac%7B3%7D%7B
emmasim [6.3K]

Answer:

-1/60

Step-by-step explanation:

\frac{11}{15}  + (- \frac{3}{4} )\\

= \frac{11}{15}  -  \frac{3}{4}\\

= \frac{44}{60}  -  \frac{45}{60}\\  (find LCM of demoninators)

= \frac{44-45}{60}\\

= \frac{-1}{60}\\

= -1/60

7 0
3 years ago
Number is a factor of 51?
soldi70 [24.7K]
Only 1 and 51 are factors of 51. 
7 0
3 years ago
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