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3 years ago

Find the solution to the system of equations.

Mathematics

2 answers:

PolarNik [594]3 years ago

7 0

B. I’m 75 percent sure

Novosadov [1.4K]3 years ago

7 0

It’s B I got it right on edge.

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What is the solution to the following system? 3x+3y=10 -9x-9y=-30

Degger [83]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We have the equations,

1. 3x+3y=10

2. -9x-9y= -30

Now, if we multiply equation 1 with -3, we will obtain equation 2.

i.e. -3×(3x+3y)= -3×10

i.e. -9x-9= -30

So, we see that both the equations are same.

The equation 3x+3y=10 will have solution for many values of x and y.

Hence, the system will have infinite number of solutions.

4 0

3 years ago

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Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

Hope it helps...

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Show how you can use the distributive property to multiply

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Marcus gardens. He pulls weeds for 18 minutes, Waters for 13 minutes, andplants for 16 minutes how many total minutes does he sp

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Shown here is the graph of which inequality? PLEASE HELPPP!

lakkis [162]

The answer to this one will be C
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4 years ago

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