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dmitriy555 [2]
3 years ago
9

Use the parallelogram below to solve for x x , then find the length of all 4 sides. figure

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
Can u show me what the parallelogram below was
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What is the answer for this question??? i need it
JulijaS [17]

Answer:

f(4)=14

Step-by-step explanation:

a) u do it by substituting 4 in places where there r 'x'

since this one say f(4) it only can go to the function which says f(x)
f(x)=4x-2
f(4)=4(4)-2, so according to BODMAS rule multiplication comes first rather than subtraction

so, f(4)=16-2=14
f(4)=14
do the others based on this, hope i explained well, if i did, please gimme brainliest :)

4 0
2 years ago
What is the answer for this -12n - (-13n)=
Ksenya-84 [330]

Answer:

n

Step-by-step explanation:

-12n - (-13n) = -12n +13n = 1n

8 0
3 years ago
Write 3 equivalent expressions for 12x-36
morpeh [17]

Answer:

1) 24x-72; 2) 6x-18; 3) 2x-9

Step-by-step explanation:

You can divide it or multiply it by whatever number it is to make it a whole number, not a decimal. Or else it will be even more difficult.

4 0
3 years ago
Solve y=x2 +7 fоr x.<br> ОА. x = t /у +7<br> ОВ. x= y +7<br> Ос. x=y-7<br> OD. х = + y -7
elena55 [62]

Answer:

x = ± \sqrt{y-7}

Step-by-step explanation:

Given

y = x² + 7 ( subtract 7 from both sides )

y - 7 = x² ( take the square root of both sides, thus

x = ± \sqrt{y-7}

5 0
3 years ago
I need help please I don’t understand
defon

9514 1404 393

Answer:

  1. ∠EDF = 104°

  2. arc FG = 201°

  3. ∠T = 60°

Step-by-step explanation:

There are a couple of angle relationships that are applicable to these problems.

  • the angle where chords meet is half the sum of the measures of the intercepted arcs
  • the angle where secants meet is half the difference of the measures of the intercepted arcs

The first of these applies to the first two problems.

1. ∠EDF = 1/2(arc EF + arc UG)

  ∠EDF = 1/2(147° +61°) = 1/2(208°)

  ∠EDF = 104°

__

2. ∠FHG = 1/2(arc FG + arc ES)

  128° = 1/2(arc FG +55°) . . . substitute given information

  256° = arc FG +55° . . . . . . multiply by 2

  201° = arc FG . . . . . . . . . subtract 55°

__

3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.

  ∠T = 1/2(arc FS -arc US)

  ∠T = 1/2(170° -50°) = 1/2(120°)

  ∠T = 60°

3 0
3 years ago
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