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schepotkina [342]
2 years ago
9

You have a pet hamster and a pet mouse. The hamster weighs 416 of a pound. The mouse weighs 116 of a pound. How much more does t

he hamster weigh than the mouse?
Mathematics
1 answer:
Harrizon [31]2 years ago
4 0

How much more does the hamster weighs than the mouse is 300 pounds.

Since we have a pet hamster and a pet mouse. We know that the hamster weighs 416 of a pound and the mouse weighs 116 of a pound.

To know how much more the hamster weighs more than the mouse, we take the difference between the weight of the hamster and the weight of the mouse.

Since the weight of the hamster = 416 pounds and the weight of the mouse equals 116 pounds.

<h3>The difference in weight</h3>

The difference in the weight d = weight of hamster - weight of mouse

= 416 pounds - 116 pounds

= 300 pounds.

So, how much more does the hamster weighs than the mouse is 300 pounds.

Learn more about difference here:

brainly.com/question/751620

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On a Saturday, a library checked out 52 books. Of the 52 books checked out, 24 of the books were fiction. What type of ratio doe
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Answer: 24/28

Step-by-step explanation:

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2 years ago
Help me on This I really need help
galina1969 [7]
3
because -8-7=-15 over -4-1=-5 
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5 0
3 years ago
A manufacturer claims that fewer than 6% of its fax machines are defective. to test this claim, he selects a random sample of 97
AfilCa [17]

Let P be the population proportion, p be the sample proportion, n be the sample size.

A manufacturer claims that fewer than 6% of its fax machines are defective. It means P=0.06

Sample size n=97 and sample proportion p=0.05

The hypothesis to be tested is

H0: P ≥ 0.06 V/s Ha: P < 0.06

Here the hypothesis for testing population proportion we use z test statistics. Z test statistics is give by

Z = \frac{p -p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}

Where p =sample proportion = 0.05

p0 = hypothesized proportion value =0.06

Using given values into test statistics we get

Z = \frac{0.05 -0.06}{\sqrt{0.06(1-0.06)/97}}

Z = -0.41

The p-value for left tailed alternative hypothesis is given by

P-value = P(z < z cal)

where zcal = Z test statistics value

Here zcal = -0.41

P-value = P(Z < -0.41)

Using z score table to find probability below z=-0.41

P-value = 0.3409

P-value for testing the given claim is 0.3409

3 0
3 years ago
A ball is kicked in the air. The height of the ball can be calculated using the equation h(t) =-16t^2+64t+190, where h is in hei
gregori [183]

Answer:

Therefore the ball strikes the ground  5.98 s after kick.          

Step-by-step explanation:

Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation h(t)=-16t^2+64t+190    where h is height in feet and t is time in second.

When the ball touches the ground then the height will be zero.

i.e h(t)=0

Therefore

-16t^2+64t+190=0

\Rightarrow -2(8t^2-32t-95)=0

Since -2≠0 then (8t^2-32t-95)=0

(8t^2-32t-95)=0    

[The solution of a quadratic equation ax²+bx+c=0 is

  x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}  here a=8, b=-32 and c=-95]                    

\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}        

\Rightarrow t =\frac{32\pm\sqrt{4064} }{16}    

Therefore   t=  5.98 or -1.98

since time can not be negative So , t=5.98 s

Therefore the ball strikes the ground  5.98 s after kick.          

5 0
3 years ago
Solve the system of equations.
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I hope this helps you

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