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xz_007 [3.2K]
3 years ago
15

Solve the following system of equations graphically on the set of axes below. Y=1/3x+6 y=-5/3x-6

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

I can not solve it in the system of the image, but i will give you the graph so you can copy it, or at least see how it is done.

First, we have the lines:

y = (1/3)*x + 6

y = (-5/3)*x - 6

To graph these lines, you must find two points for the lines and then draw a line that connects the points.

To do it, you can evaluate each line in two different values of x, for example for the first line we can have:

y(0) = (1/3)*0 + 6 = 6   (then we have the point (0, 6))

y(3) = (1/3)*3 + 6 = 7    (then we have the point (3, 7))

And for the second line, we will have:

y(0) = (-5/3)*0 - 6 = -6 (then we have the point (0, -6))

y(3) = -(5/3)*3 - 6 = -11 (then we have the point (-3, -11))

Now with those points we can graph the lines, and the solution of the system of equation will be the point where the two lines intersect.

The graphs of the lines are shown below:

Where the grey line is the first one, and the green is the second.

In the graph, you can see that the lines intersect in the point (-6, 4)

Then the solution for the system is x = -6, and y = 4.

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Answer:

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Step-by-step explanation:

Given

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9 = 3² ⇒ b = 3, thus

4x² - 9 = (2x - 3)(2x + 3) ← in factored form

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The ratio of the measures of the sides of a
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Answer:

The length of the sides are 8 , 32 , 36

Step-by-step explanation:

Ratio of sides = 2  : 8 : 9

The sides are 2x , 8x , 9x

Perimeter of triangle = 76 inches

2x+ 8x + 9x  = 76

              19x = 76

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6 0
3 years ago
Read 2 more answers
The vertices of a triangle are A(1, –9), B(0, –3), C(–4, –5). Fine the length of each side. What type of triangle is triangle AB
Alenkinab [10]

Answer:

AB = √37

BC = 2√5

AC = √41

Type: SCALENE TRIANGLE

Step-by-step explanation:

Given the coordinates

A(1, –9), B(0, –3), C(–4, –5)

We are to find the length of each sides first. Using the formula for calculating the distance between two points, we will have;

For A(1, –9) and B(0, –3)

AB = √(-3+9)²+(0-1)²

AB = √6²+(-1)²

AB = √36+1

AB = √37

For coordinates B(0, –3) and C(–4, –5)

BC = √(-5+3)²+(-4-0)²

BC= √(-2)²+(-4)²

BC = √4+16

BC = √20

BC = 2√5

For coordinates  A(1, –9), C(–4, –5)

AC = √(-5+9)²+(-4-1)²

AC= √(4)²+(-5)²

AC = √16+25

AC = √41

<em>Since the sides of the triangles are all different, hence the triangle is a SCALENE triangle</em>

8 0
3 years ago
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