Suppose :
2^x = t ..**&**.. 3^y = u
_____________________________
t + u = 9 × 3 3t + 3u = 27
=====》
2t - 3u = 8 2t - 3u = 8
+ __________
5t = 35
5 × t = 5 × 7
t = 7
&
u = 2
________________________________
Thus :
2^x = 7 ===》 x = Log _ 2 { 7 }
3^y = 2 ===》 y = Log _ 3 { 2 }
Answer: it's either a or b
Step-by-step explanation:
I am not really sure but I think it's A because they said one of each card has been placed in a box. Then I said it's B because there are four of each card of ace, kind, jack and a queen in a standard deck of cards
Answer:
p = -2
Step-by-step explanation:
5p - 10 = + 4(1 + 3p)
first get rid of the bracquetes:
5p - 10 = + 4*1 + 4*3p
5p - 10 = + 4 + 12p
subtract left and right of = sign by 5p
5p -5p - 10 = + 4 + 12p -5p
0 - 10 = + 4 + (12p -5p)
subtract left and right of = sign by 4
-10 -4 = 4 -4 + ( 7p )
re arrange
7p + 0 = -14
divide left and right of = sign by 7
7/7 p = -14/7
p = -2
Answer:thats your answer
Step-by-step explanation:
