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Leno4ka [110]
3 years ago
10

A town in east Texas received 35 inches of rain in two weeks. If it kept raining at this rate for a 31−day month, how much rain

did the town receive? Round your answer to the nearest inch
The town received approximately [???] inches of rain during a 31−day month.​
Mathematics
1 answer:
zvonat [6]3 years ago
8 0
The answer should be 72.5 because you add 35 inches of rain for two weeks twice to make a month and to get the extra day divide 35 inches of rain for two weeks which is 35/14 days and that equals 2.5 inches of rain per day. Finally multiply 35 times 2 to make a month = 70 and now add 70+2.5 for your extra month day = to your ANSWER: 72.5

Hope this helps
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SOMEONE HELP ASAP! IM STUCKKKKKK
fredd [130]

Answer: B) increasing for x < -4/3 and x > 4/3

                   decreasing for -4/3 < x < 4/3

<u>Step-by-step explanation:</u>

Graph the equation and follow the curve from left to right. If you are going up, it is increasing. If you are going down, it is decreasing.

Refer to the image below. Red is increasing. Blue is decreasing.

The vertices are at: x = -4/3 and x = 4/3

6 0
3 years ago
What is the slope of the line between (−4, 4) and (−1, −2)? (1 point)
SCORPION-xisa [38]
The slope of the line is -2.



3 0
3 years ago
Read 2 more answers
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





4 0
3 years ago
Identify an equation in point-slope form for the ine parallel to y = -2/3 x+8 that
zlopas [31]

Answer:

y +5 = -\frac{2}{3}(x - 4)

Step-by-step explanation:

Given

y = -\frac{2}{3}x + 8

Point (4,-5)

Required

Determine the line equation

From the question, we understand that the line is parallel to y = -\frac{2}{3}x + 8

This implies that they have the same slope, m

A linear equation is:

y = mx + b

Where

m = slope

By comparison: y = mx + b and y = -\frac{2}{3}x + 8

m = -\frac{2}{3}

Next, we determine the line equation using:

y - y_1 = m(x - x_1)

Where

(x_1,y_1) = (4,-5) and m = -\frac{2}{3}

y - (-5) = -\frac{2}{3}(x - 4)

y +5 = -\frac{2}{3}(x - 4)

Hence,

<em>Option C is correct</em>

<em />

4 0
3 years ago
2,23,27,29,30,32,32,34,35,96 select the two outliers
viva [34]
96 and 2 cause they are WAY off. 
5 0
3 years ago
Read 2 more answers
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