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3 years ago

If x and y are both negative when is x-y positive

1 answer:

7 0

X-y is positive when y is further away from 0, compared to x. In other words, when y is a larger negative

For example
x = -2
y = -5

x-y = -2-(-5) = -2+5 = 3

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Help is very much needed :)

ioda

Answer:

Step-by-step explanation:

10/5 ×/3 multiply 10×3 and than divide by 5

or another way start with multiplying 5 and n equaling 5n=

than 10× 3= 30 so you're left with 5n=30 divied 30 by 5 equalling 6

so x=6

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3 years ago

What is the skipping sequence of 90,92,__,__,99,__

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3 years ago

Which is equivalent to 256 3/4? A.4 B.12 C.64 D.192

posledela

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2 years ago

Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL

scoray [572]

Answer:

$8(x^2+y^2)-4x-30y+23=0$

Step-by-step explanation:

Distance formula

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let P(x, y) = any point on the locus

Let A = (0, 2)

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

$PA=\dfrac{1}{3}PB$

Therefore, using the distance formula:

$\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}$

Square both sides:

$\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]$

$\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)$

Multiply both sides by 9:

$\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9$

$\implies 8x^2+8y^2-4x-30y+23=0$

$\implies 8(x^2+y^2)-4x-30y+23=0$

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2 years ago