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3 years ago

If x and y are both negative when is x-y positive

1 answer:

7 0

X-y is positive when y is further away from 0, compared to x. In other words, when y is a larger negative

For example
x = -2
y = -5

x-y = -2-(-5) = -2+5 = 3

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(03.01) Factor completely 2x^5 + 10x^4- 22x^3

kakasveta [241]

Answer:

Step-by-step explanation:

2x^3(x^2 + 5x - 11)

5 0

2 years ago

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

Answer: The half life of the sample of phosphorus-32 is $14.28days^{-1}$

Step-by-step explanation:

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

7 0

3 years ago

Find all the zeros of the equation -3x^4 + 27x^2 + 1200 = 0

guajiro [1.7K]

Answer:

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

$\displaystyle -3x^4+27x^2+1200=0$

If we call $y=x^2$ , our equation becomes a second-degree equation

$\displaystyle -3y^2+27y+1200=0$

Dividing by -3

$\displaystyle y^2-9y-400=0$

Factoring

$\displaystyle (y-25)(y+16)=0$

It leads to these solutions

$\displaystyle y=25\ ,\ y=-16$

Taking back the change of variable, we have for the first solution

$\displaystyle x^2=25\Rightarrow x=-5,x=5$

Now for the second solution, we get imaginary (complex) values

$\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i$

Summarizing, the four solutions for x are

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

5 0

2 years ago

Amir is sorting his stamp collection. He has made a chart of what countries the stamps are from

natulia [17]

Answer:

Step-by-step explanation:

Given that Amir is sorting his stamp collection. He has made a chart of what countries the stamps are from

He got results as

France 1/3

Morocco 5/12

Spain 1/6

To find out what fraction of Amir's stamps are from France, Morocco, or Spain, we have to simply add the three as there is common element between any two pairs

Hence answer is

$\frac{1}{3} +\frac{5}{12} +\frac{1}{6}\\ =\frac{11}{12}$

8 0

2 years ago

Read 2 more answers

Help me ???? Really need the help i dont remember learning this

vlada-n [284]

Hmmmm

the 1 in 435.15 is worth 0.1 or 1/10

1/10 of 1/10 is 1/10 times 1/10 or 1/100 or 0.1/10 or 0.01/1 or 0.01

so we want one with the 1 that is 2 spaces to the right of the decimal
that is choice H
remember, when you divide by 10, move the decimal to the left 1 space

H is the answer

4 0

3 years ago