Answer: True
Explanation: <u><em>The scenario given in the question is an example of global advertising campaign.</em></u>
Global advertising can be referred to as advertising on global scale unification or captivating marketable benefit of worldwide operational variances, similarities and chances in order to accomplish global aims. It is also known as a method where similar universal message is functional at a global scale<u><em>.</em></u>
Answer:
a. 28.7 millions
b. 20.4 millions
c. 0.9231, or 92.31%
Explanation:
a. How much of the population is older than 16? million
Number of population older than 16 = Total population - Children under the age of 16 = 35.4 – 6.7 = 28.7 millions
b. What is the size of the labor force? million
Labour force = Employed + Unemployed = 18.5 + 1.9 = 20.4 millions
c. What is the labor force participation rate?
Working age population = Total population – Children under the age of 16 – Retirees = 35.4 – 6.7 – 6.6 = 22.1 millions
Labor force participation rate = Labor force ÷ Working age population = 20.4 ÷ 22.1 = 0.9231, or 92.31%
Answer:
The answer is: Quantitative easing
Explanation:
Quantitative easing is a type of monetary policy in which the central bank purchases predetermined quantity or amount of government securities or other financial assets to increase the supply of money, encourage lending and investment and inject liquidity into the economy. It is a unconventional monetary policy which is used when the standard expansionary monetary policy is ineffective and during low or negative inflation.
<u>Therefore, the given policy is known as </u><u>Quantitative easing.</u>
Answer:
Value of x maximising profit : x = 5
Explanation:
Cost : C(x) = x^3 - 6x^2 + 13x + 15 ; Revenue: R(x) = 28x
Profit : Revenue - Cost = R(x) - C(x)
28x - [x^3 - 6x^2 + 13x + 15] = 28x - x^3 + 6x^2 - 13x - 15
= - x^3 + 6x^2 + 15x - 15
To find value of 'x' that maximises total profit , we differentiate total profit function with respect to x & find that x value.
dTP/dx = - 3x^2 + 12x + 15 = 0 ► 3x^2 - 12x - 15 = 0
3x^2 + 3x - 15x - 15 = 0 ► 3x (x +1) - 15 (x + 1) = 0 ► (x+1) (3x-15) = 0
x + 1 = 0 ∴ x = -1 [Rejected, production quantity cant be negative] ;
3x - 15 = 0 ∴ 3x = 15 ∴ x = 15/3 = 5
Double derivate : d^2TP/dx^2 = - 6x + 12
d^2TP/dx^2 i.e - 6x + 12 at x = 5 is -6(5) + 12 = - 30+ 12 = -8 which is negative. So profit function is maximum at x = 5
Answer:
Let me give you an example of a segment addition problem that uses three points that asks the student to solve for x but has a solution x = 20.
First, I assumed values for each x, y and z and then manipulated their coefficients to get the total at the end of each equation.
20 + 10 +30 = 60
40 + 0 + 40 = 80
40 + 10 = 50
Then exchangeing these numbers into values and we have the following equation.
x + 2y + 3z = 60
2x + 4z = 80
2x + z = 50 so its easy
If you will solve them manually by substituting their variables into these equations, you can get
x = 20
y = 5
z = 10
Explanation:
