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BARSIC [14]
3 years ago
8

Which number line could help you find the distance between (7,4) and (3, 4)?

Mathematics
2 answers:
nordsb [41]3 years ago
5 0

Answer:

Pick the number line with points at 3 and 7 :)

Step-by-step explanation:

Leya [2.2K]3 years ago
3 0

Answer: 4

Step-by-step explanation:

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Help please this was due yesterday (i have more needing done)
prohojiy [21]

Answer:

the answer is x=6

Step-by-step explanation:

5x+4+8x-3=79

13x+1=79

13x=78

x=6

7 0
4 years ago
What is 12- 33/4 for my I ready
iogann1982 [59]
12 = 48/4

48/4 - 33/4 = 15/4 = 3 3/4
3 0
3 years ago
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MATH QUESTION!! PLEASE HELP
svlad2 [7]

bro i literally had the same question about this

you in honors or something? sry i only got A

I might have B later on or something

Answer:

A.

41.125π ≈ 129

149.875π ≈ 471

Step-by-step explanation:

Surface area of smaller ganza:

3.5/2 = 1.75 x 1.75 = 3.0625 x 3.14 = 9.61625 x 2 = 19.2325

1.75 x 10 = 17.5 x 3.14 = 54.95 x 2 = 109.9 + 19.2 = 129 (Rounded)

Surface area of larger ganza:

5.5/2=2.75 x 2.75 = 7.5625 x 3.14 = 23.74625 x 2 = 47.4925

2.75 x 24.5 = 67.375 x 3.14 = 211.5575 x 2 = 423.115 + 47.4925 = 471 (Rounded)

π

129/3.14 = 41.125

471/3.14 = 149.875

4 0
2 years ago
Read 2 more answers
Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a
Bumek [7]

Answer:

0.381 is the probability that the number of drivers will be at most 18.                          

Step-by-step explanation:

We are given the following information in the question:

The number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20.

  • The Poisson distribution is the discrete probability distribution of the number of events occurring in a given time period, given the average number of times the event occurs over that time period.
  • The variance of Poisson distribution is equal to the mean of Poisson distribution.

a) P(number of drivers will be at most 18)

Formula:

P(X =k) = \displaystyle\frac{\mu^k e^{-\mu}}{k!}\\\\ \mu \text{ is the mean of the distribution}

P( x \leq 18) =P(x=0) + P(x =1) + P(x = 2) + ... + P(x = 18)\\\\= \displaystyle\frac{20^0 e^{-20}}{0!} + \displaystyle\frac{20^1 e^{-20}}{1!} +...+ \displaystyle\frac{20^{18} e^{-20}}{18!}\\\\ = 0.381

Thus, 0.381 is the probability that the number of drivers will be at most 18.

3 0
4 years ago
A game lasts 5 hours. Ali played 4 of these games,
kkurt [141]

Answer:

20. hours

Step-by-step explanation:

3 0
3 years ago
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