Answer:
3 miles on Monday
2¹/₁₀ miles on Tuesday
3⁹/₂₀ miles on Wednesday
Step-by-step explanation:
We are told that Bonnie runs 1⅔ (⁵/₃) times as far as John each day
This means that John runs ³/₅ times as far as Bonnie.
MONDAY:
Bonnie runs 5 miles on Monday, therefore, John runs:
³/₅ * 5 = 3 miles
TUESDAY:
Bonnie runs 3½ (⁷/₂) miles on Tuesday, therefore, John runs:
³/₅ * ⁷/₂ = ²¹/₁₀ = 2¹/₁₀ miles
WEDNESDAY:
Bonnie runs 5³/₄ (²³/₄) miles on Wednesday, therefore, John runs:
³/₅ * ²³/₄ = ⁶⁹/₂₀ = 3⁹/₂₀ miles
Take 30.16-17.56. Theb divide by 5
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:

Hence the derivative is:

For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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1.301
Explanation:
Given:
and 
Note that from the properties of logarithms,





