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seraphim [82]
3 years ago
9

Hey turtle cow i got a question you+the band=happy

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0
No happy at all !!!!!!
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At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
Daniel [21]

Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
3 years ago
A new movie opened in a local theater. On opening day, 985 people saw the movie. Each day after opening day, the number of peopl
zysi [14]

Answer:

About 3891 people saw that movie.

Step-by-step explanation:

Day 1: 985 people

Day 2: (985*8)/10 (20% gone) = 788

Day 3: (788*8)/10 (20% gone) = 630.4

Day 4: (630.4*8)/10 (20% gone) = 504.32

Day 5: (504.32*8)/10 (20% gone) = 403.456

Day 6: (403.456*8)/10 (20% gone) = 322.7648

Day 7: (322.7648*8)/10 (20% gone) = 258.21184

Adding this up:

985+788+630.4+504.32+403.456+322.7648+258.21184=

985+788+630+504+403+323+258=3891

4 0
3 years ago
Erin writes the set of ordered pairs below. The set represents a function.
tino4ka555 [31]
Point A shows that she is incorrect.
With functions, you can perform the "straight line test through each point. If the line goes through both points, you know it's not a function.
If we plotted point A, it'd fail the straight line test because the given point (-6, 7) already has -6 as an x value.
Hope this helps!
7 0
3 years ago
A photo of a beetle in a science book is increased to 535​% as large as the actual size. If the beetle is 14 ​millimeters, what
AnnZ [28]

Answer: 74.9 millimeters

Step-by-step explanation:

From the question, a photo of a beetle in a science book was.increased to 535​% as large as its actual size and the beetle.has a actual size of 14 ​millimeters,

The size of the beetle on the photo will be 535% of 14 millimeters. This will be:

= 535% of 14

= 535/100 × 14

= 5.35 × 14

= 74.9 millimeters

4 0
3 years ago
What is the approximate value of q in the equation below?
gayaneshka [121]

<u>Given</u>:

The given equation is q+\log _{2}(6)=2 q+2

We need to determine the approximate value of q.

<u>Value of q:</u>

To determine the value of q, let us solve the equation for q.

Hence, Subtracting \log _{2}(6) on both sides of the equation, we get;

q=2 q+2-\log _{2}(6)

Subtracting both sides of the equation by 2q, we have;

-q=2-\log _{2}(6)

Dividing both sides of the equation by -1, we have;

q=\log _{2}(6)-2

Now, substituting the value of log_2(6)=2.585, we have;

q=2.585-2

Subtracting the values, we get;

q=0.585

Thus, the approximate value of q is 0.585

Hence, Option C is the correct answer.

5 0
3 years ago
Read 2 more answers
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