Are there numbers?
If there are numbers add b and c then add d to the a then divide a with the b and c and you get the answer if that even makes sense
Option B:
The perimeter of ΔABC is 28 units.
Solution:
AD = 5, DC = 6 and AB = 8
AD and AE are tangents to a circle from an external point A.
BE and BF are tangents to a circle from an external point B.
CD and CF are tangents to a circle from an external point C.
<em>Tangents drawn from an external point to a circle are equal in length.</em>
⇒ AD = AE, BE = BF and CD = CF
AE = 5
AE + BE = AB
5 + BE = 8
Subtract 5 from both sides.
BE = 3
BE = BF
⇒ BF = 3
CD = CF
⇒ CF = 6
Perimeter of the polygon = AE + BE + BF + CF + CD + AD
= 5 + 3 + 3 + 6 + 6 + 5
= 28
The perimeter of ΔABC is 28 units.
Option B is the correct answer.
Use Y=-2/3x + b
and then plug in (-7,-4)
-7 is x, so plug that in for x
Y=-2/3(-7) + b
and plug in y, -4
-4=-2/3(-7) +b
plug into calculator and then solve algebraically!
b doesn’t mean anything, it’s just what i used for the y axis, really you could use any letter
Answer:
Zero's are X = 2 and X = -7
Step-by-step explanation:
you would set the factorized parts equal to zero, as in x - 2 = 0 and x + 7 = 0, then solve for x, and whatever you get is where y will be zero
Answer: (x, y) = (2, 3)
This is the system of equations 2x - 3y = -5, 5x - 2y = 4. Multiply the first equation by 2 and the second equation by 3 to get 4x - 6y = -10, 15x - 6y = 12. Now we can use elimination: subtract the equations to get -11x = -22, so x = 2. 2x - 3y = 2(2) - 3y = 4 - 3y = -5, so 3y = 9 and y = 3. The solution is (2, 3).
i hope this helped! :D
