Answer:
The answer is D.. 2^0
Step-by-step explanation:
i had the same question in my program
<h3>
Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that 
The weather in the three areas were all very similar on that day in particular.
If p= 38
You need four sides to equal that
11 is length so that means two sides are 11
11+11= 22
So that means you need two more equal numbers that will finish making up the 22
38-22= 16
But two sides make up 16
16 divides by 2 is 8
So THE WIDTH IS 8
Answer:
Step-by-step explanation:
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