Answer:
When the price of a ticket = $0 or $40, there will be no revenue.
The revenue will be $500 if each ticket cost $37.3 or $2.68
Step-by-step explanation:
Let R(p) = p(200-5p)
when R(p) = 0
p(200-5p) = 0
p = 0 or 200-5p = 0
When the price of a ticket = $0 or $40, there will be no revenue.
when R(p) = 500
200p - 5p² = 500
5p² - 200p + 500 = 0
p = $37.3 or $2.68 (3 sig. fig.)
The required prices are $37.3 and $2.68
-3(5-9v)=25+7v
-15+27v=25+7v
+15 +15
27v=40+7v
-7v -7v
-20v=40
divide 40 by -20
v=-2
And that’s the answer you need to stop being mean to me
leci:ANWSER:idk really wanna anwer right now prople later
Answer:
B
Step-by-step explanation:
