Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
= 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
Answer:
The quadratic equation is x^2 -12x -120 = 0
where x represents the length of the field
Step-by-step explanation:
We want to make an expression in terms of a quadratic equation;
Let the length of the field be x mm , then the width will be (x-12) mm
Mathematically , the area of the field will be L * B
Thus;
x * (x-12) = 120
That gives;
x^2 -12x = 120
x^2 -12x -120 = 0
Answer:
y = one-third x + 3
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Slope Formula: 
Step 1: Find slope <em>m</em>
m = (4 - 1)/(3 + 6)
m = 3/9
m = 1/3
y = 1/3x + b
Step 2: Find <em>b</em>
4 = 1/3(3) + b
4 = 1 + b
b = 3
Step 3: Rewrite
y = 1/3x + 3
