Question

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Answer 1

Answer:

$x = \frac{6 \pm \sqrt{(-6)^2 - 4(3)(8)}}{2(3)}$

Step-by-step explanation:

Given the equation, $3x^2 - 6x + 8 = 0$, the quadratic formula for solving this equation is given as:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Where,

a = 3

b = -6

c = 8

Plug in the above values into the quadratic formula.

$x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(3)(8)}}{2(3)}$

$x = \frac{6 \pm \sqrt{(-6)^2 - 4(3)(8)}}{2(3)}$