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Sati [7]
3 years ago
14

Design the image of UAE Mars mission-rocket in the following graph sheet and write

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

i hope these 3 images helps

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Pythagorean Theorem Determine the length of the missing side?
Naily [24]
The answer should be 12.2
7^2+10^2=c^2
49+100=c^2
149=c^2
12.2=c
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3 years ago
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How to find the circumference of a circle​
Romashka [77]
  1. C = πd. In this equation, "C" represents the circumference of the circle, and "d" represents its diameter. That is to say, you can find the circumference of a circle just by multiplying the diameter by pi. Plugging π into your calculator will give you its numerical value, which is a closer approximation of 3.14 or 22/7.
  2. The radius is half as long as the diameter, so the diameter can be thought of as 2r. Keeping this in mind, you can write down the formula for finding the circumference of a circle given the radius: C = 2πr. In this formula, "r" represents the radius of the circle. Again, you can plug π into your calculator to get its numeral value, which is a closer approximation of 3.14.
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3 years ago
(x+3)^2=4
GalinKa [24]

Answer:

x = -1, -5

Step-by-step explanation:

{(x + 3)}^{2}  = 4 \\  =  >  {x}^{2}  + 2 \times x \times 3 +  {3}^{2}  = 4 \\  =  >  {x}^{2}  + 6x + 9 = 4 \\  =  >  {x}^{2}  + 6x = 4 - 9 \\  =  >  {x}^{2}  + 6x =  - 5 \\  =  >  {x}^{2}  + 6x  + 5 = 0 \\  =  >  {x}^{2}  + 5x + x + 5 = 0 \\  =  > x(x + 5) + 1(x + 5) = 0 \\  =  > (x + 1)(x + 5) \\  =  > x =  - 1 \:  \: or \:  \:  - 5

Hope it helps.

Don't forget to click the "Brainliest" button if you like my answer.

6 0
3 years ago
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1/5(x+2)+2x=6x-10 what does x=
Ber [7]
The answer to this problem is x = 52/19 = 2.737... I hope...
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3 years ago
Derivative of (4e)^x
love history [14]

we are given the expression (4e) ^x and is asked to derive the expression. we distribute first the equations resulting to 4^x e^x = y. using the rule of products,
y = 4^x e^xy' =  4^x ln 4 e^x + 4^x e^x
The final answer is y' =  4^x ln 4 e^x + 4^x e^x
6 0
3 years ago
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