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3 years ago

7

Plsssssssssssssssssssss help meeeeeee on thisssss????????????

1 answer:

balu736 [363]3 years ago

8 0

11 3/4 hope it helps

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Huey works 175 hours each month and earns $14.25 per hour after taxes. His monthly budget is shown. How much money is left over

steposvetlana [31]

For this case we have the following equation:
y = 14.25x
Where,
x: number of hours
y: total salary
For x = 175 we have:
y = 14.25 * (175)
y = 2493.75
The amount of money for unexpected expenses is:
unplanned expenses = 2493.75 - 1250 - 200 - 350 - 400 - 225 - 300
unplanned expenses = -231.25 <0
We note that there is no money left for unexpected expenses
Answer:
there is nothing left over

3 0

4 years ago

Do this problem please, its due today!

wel

Answer:

7

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP AND BE REAL I WILL GIVE BRAINLY. Simplify 8.7+ (1.5) ²+4(3.5+6.2)-3.1 - 3.5

kifflom [539]

Answer:

43.15

Step-by-step explanation:

See attachment below

8 0

3 years ago

Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random

Maurinko [17]

Answer:

D)

$(0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })$

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the random sample size 'n' = 50

The sample proportion

$p^{-} = \frac{32}{50} = 0.64$

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

$(p^{-} - Z_{0.90} \sqrt{\frac{p(1-p)}{n}, } , p^{-} +Z_{0.90} \sqrt{\frac{p(1-p)}{n} })$

<u><em>Step(ii):-</em></u>

Level of significance = 0.90

Z₀.₉₀ = 1.645

$(0.64 - 1.645 \sqrt{\frac{0.64(1-0.64)}{50}, } , 0.64 +1.645 \sqrt{\frac{0.64(1-0.64)}{50} })$

$(0.64 - 1.645 \sqrt{\frac{0.64(0.36)}{50}, } , 0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })$

(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)

(0.52846 , 0.75166)

<u><em>Final answer:-</em></u>

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

5 0

3 years ago

Five greater than or equal to x minus two

Vadim26 [7]

5≥x-2
add 2 toboth sides
7≥x
x≤7

5 0

4 years ago