Answer:
Part 1)
-----> solution set {7,2}
Part 2)
-----> solution set {-2,-7}
Part 3)
-----> solution set {2,-5}
Part 4)
----> solution set {2,-7}
Part 5)
----> solution set {-2,7}
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
Part 1)
in this problem we have
so
substitute in the formula
![a=\frac{9(+/-)\sqrt{-9^{2}-4(1)(14)}} {2(1)}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B9%28%2B%2F-%29%5Csqrt%7B-9%5E%7B2%7D-4%281%29%2814%29%7D%7D%20%7B2%281%29%7D)
![a=\frac{9(+/-)\sqrt{25}} {2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B9%28%2B%2F-%29%5Csqrt%7B25%7D%7D%20%7B2%7D)
![a=\frac{9(+)5} {2}=7](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B9%28%2B%295%7D%20%7B2%7D%3D7)
The solution set is {7,2}
Part 2)
in this problem we have
so
![a=1\\b=9\\c=14](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D9%5C%5Cc%3D14)
substitute in the formula
The solution set is {-2,-7}
Part 3)
in this problem we have
so
substitute in the formula
The solution set is {2,-5}
Part 4)
in this problem we have
so
substitute in the formula
The solution set is {2,-7}
Part 5)
in this problem we have
so
substitute in the formula
The solution set is {-2,7}