What sequence begins with the number five and then adds five each time?

Jennifer has a taco stand.she found that her daily costs can be modeled by C(x)=x^2-40x+610. if she wants to keep her daily cost

Svetllana [295]

Plug in 300 for C(x), to get:
300= $x^{2} -40x=610$
Then subtract to get: 0= $0= x^{2} -40x+310$
Then use the quadratic formula and plug everything in. Use a calculator to simplify.

You'll get two answers: 29.486 and -0.513.
Since you can't sell "negative" tacos, use the positive solution
Around 29-30 tacos.

8 0

2 years ago

Find the number of ways to listen to four CDs from a selection of 8 CDs. A) 1680 B) 336 C) 70 D) 50 pls aslo explain why..

777dan777 [17]

Answer:

a) 1680

The number of ways to listen to four CDs from a selection of 8 CDs = 1680

Step-by-step explanation:

Explanation:-

Given data the number of CD' s n = 8

We have to selected '4' CD' s from total '8' CD's

By using permutations

The number of ways to listen to four CDs from a selection of 8 CDs.

= $8_{P_{4} }$

we know that

$n_{P_{r} } = \frac{n!}{(n-r)!}$

$8_{P_{4} } = \frac{8!}{(8-4)!} = \frac{8 X 7 X 6 x 5 X 4!}{4!} = 1680$

The number of ways to listen to four CDs from a selection of 8 CDs = 1680

7 0

3 years ago

Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}$

⇒ $\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}$

⇒ $(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

⇒ $(x-2)(x-6) =0$ or, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

If, (x-2)(x-6) =0, then x=2 or x=6

If, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$ , then $x^{2} -5x-2=4$

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0

3 years ago

The manufacturer of a metal stand for home TV sets must be sure that its product will not fail under the weight of the TV. Since

ikadub [295]

Answer:

a) "This is an upper-tail test because the company wants to show the stands will hold 525 pounds (or more) easily."

b) "They will decide the stands are safe when they're not."

c) "They will decide the stands are unsafe when they are in fact safe."

Step-by-step explanation:

a) As the alternative hypothesis Ha is μ>575, the rejection region lays in the upper tail. Then, it is an upper-tail test.

They are testing the claim that the stand supports an average of 575 pounds or more, and are looking for statistical evidence for that claim.

"This is an upper-tail test because the company wants to show the stands will hold 525 pounds (or more) easily."

b) A Type I error happens when a true null hypothesis is rejected.

This would mean that a stands that doesn't really hold 575 pounds or more has passed the test. The stand would appear more safe than it is.

"They will decide the stands are safe when they're not."

c) A Type II error happens when a false null hypothesis failed to be rejected. In this case, a safe stand, that suports 575 pounds or more, does not pass the test.

"They will decide the stands are unsafe when they are in fact safe."

4 0

3 years ago

A community center rents their hall for special events. They charge a fixed fee of $200 plus an hourly fee of $22.50. Lin has $3

Karo-lina-s [1.5K]

Answer:

No, 6 hours would cost $335, 35 over her limit of $300.

Step-by-step explanation:

she has to pay $200 plus 22.50 for every hour she rents. So, if she rents for 6 hours, she has to pay $200 + 6(22.50) or $200 + 135=335. She only has $300 so she can’t afford the event.

3 0

2 years ago