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Nadya [2.5K]
3 years ago
15

8. The Listening Example is one of A. 27 I B. 24 preludes in this set, Opus 28. C. 20 D. 28​

Mathematics
1 answer:
stira [4]3 years ago
4 0

Answer:

28

Step-by-step explanation:

I'm not sure sorry..........

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Pls hurry!!!<br> I dont wanna fail...
Phantasy [73]
Answer is 180
2x2 is 4 4x9 is 36 36x5 is 180
8 0
3 years ago
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An arithmetic sequence has t1 = 3, t2 = 10. Find tn, Sn.
Softa [21]

Answer:

see explanation

Step-by-step explanation:

the n th term of an arithmetic sequence is

t_{n} = t_{1} + (n - 1)d

given t_{1} = 3 and t_{2} = 10, then

t_{2} = 3 + d = 10 ⇒ d = 10 - 3 = 7

t_{n} = 3 + 7(n - 1) = 3 + 7n - 7 = 7n - 4

the sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2}[2t_{1} + (n - 1)d ]

                        = \frac{n}{2}[(2 × 3) + 7(n - 1) ]

                        = \frac{n}{2}(6 + 7n - 7 )

                        = \frac{n}{2}(7n - 1)

                        = \frac{7}{2} n² - \frac{1}{2} n



7 0
3 years ago
A herd of 52 horses has 12 white and some black horses. What is the ratio of white to black horses​
Kryger [21]

Answer:

If there are 12 white horses in 5 a herd of 52 horses, there will be 40 black horses if there aren't any other color horses.

The ratio will be 40 : 12

To simplify, it will be 10 : 3

5 0
3 years ago
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Please solve I cannot solve this for the life of me
Paul [167]

Answer:

  • f(x) = x^5
  • g(x) = 2x -6 . . . . . and see below for other possible definitions

Step-by-step explanation:

You are given an expression for the composition H(x) = f(g(x)) and asked to decompose it into two functions. One way to do that is to look at what is being done to the variable in the function H(x):

  • the variable is multiplied by 2
  • 6 is subtracted from the product
  • the difference is raised to the 5th power.

One of the ways to create the functions g(x) and f(x) is to start at the top of this list and work your way down. Any subset of these transformations can be made into g(x). Then the rest of them are made into f(x).

__

For example, using

  g(x) = 2x

Then the rest of the list is f(x):

  f(x) = (x-6)^5

so when you put 2x as the argument for f(x), you get ...

  H(x) = f(g(x)) = f(2x) = (2x -6)^5 . . . . . the function we want.

__

We could also do the first two steps of our list as g(x):

  g(x) = 2x -6

  f(x) = x^5

so

  H(x) = f(g(x)) = f(2x -6) = (2x -6)^5

__

If we like, we can factor the expression for H(x):

  H(x) = (2(x -3))^5 = 32(x -3)^5

Using the methods above, we could write ...

  g(x) = x -3

  f(x) = 32x^5

so

  H(x) = f(g(x)) = f(x -3) = 32(x -3)^5

__

The multiplication and the addition can be made into several parts. We could choose ...

  g(x) = (1/4)x -1

  f(x) = (8x +2)^5

so

  H(x) = f(g(x)) = f(1/4x -1) = (8(1/4x -1) +2)^5 = (2x -6)^5

4 0
3 years ago
Is this also correct, if it is wrong please help
Elenna [48]
That is all correct, good job!
5 0
3 years ago
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