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3 years ago

Please anythign would be helpful fast ill mark brainliest

Mathematics

1 answer:

saveliy_v [14]3 years ago

5 0

I believe it is 180° around H and translate 2 up 5 right

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Please helppppp meeeee

algol [13]

Answer:

(1)

$V = \pi {r}^{2} h \\ {r}^{2} = \frac{V}{\pi \: h} \\ r = \sqrt{ \frac{V}{\pi \: h} }$

6 0

3 years ago

Nikki and Jonathan both solve this system of equations:

xxTIMURxx [149]

Answer:

Jonathan's solution $(0.4,2.12)$ is correct.

Step-by-step explanation:

Given system of equations are:

$y = -2.7x+3.2\ \ \ \ \ \ \ y=1.3x +1.6$

Now

The graph of the linear equation $y= -2.7x+3.2$ cuts the y-axis at the point $(0,3.2)$ and x-axis at $(1.185,0)$

And the graph of the linear equation $y= 1.3x+1.6$ cuts the y-axis at the point $(0,1.6)$ and x-axis at $(-1.231,0)$

And their point of intersection is $(0.4,2.12)$

And this is Jonathan's solution.

We can see from graph that point of intersection is $(0.4,2.12)$

4 0

3 years ago

The scale on a map is 1 cm : 6 km. If two cities are 13 cm apart on the map, what is the actual distance between the cities?

OlgaM077 [116]

Its easy, multiply 6km by 13cm and you would get 78

8 0

3 years ago

A figure with vertical line symmetry is placed on the coordinate plane. Given that the points (–8, –4) and (–3, –4) are on the e

nevsk [136]

Based on the description, the edges lying on those coordinates can be considered end points to a line. In this scenario, we can apply the midpoint formula to find the coordinates that lies on the vertical symmetry.

Midpoint formula: (x1+x2) / 2 for the x coordinate
(y1+y2) / 2 for the y coordinate

After calculating this, we obtain (-5.5, -4) as our midpoint. Hence the answer is letter A.

3 0

4 years ago

Read 2 more answers

Let Y1 and Y2 have the joint probability density function given by:

Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) = 9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1, 0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 = ∫∫k(1 − y2) dy1*dy2 = k ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)- (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)= 9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = 9/16

8 0

3 years ago