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Sveta_85 [38]
2 years ago
8

Solve z^3=27 it's a complex number ​

Mathematics
2 answers:
34kurt2 years ago
8 0

Answer:

-3i^2

Step-by-step explanation:

(-3i^2) ^3=-(3*(-1)) ^3=-(-3)^3=-(-27)=27

MrMuchimi2 years ago
4 0

Answer:

z³=27

³√z³=³√27

z=3

Step-by-step explanation:

z³=27

³√z³=³√27

z=3

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There are 1200 students at Sophie’s school. One student’s name will be drawn at random to win a new bike. Hannah and Ethan are S
fomenos
Hi Mackenzie. 

Given that we have a probability question with the term "or", we are going to be adding individual probabilities.
We have Ethan, Hannah, and Sophie all included with the drawing.
This means we need to add each of their individual probabilities, 1/1200, together.

1/1200 + 1/1200 + 1/1200 = 3/1200;
To simplify: 1/400

Your answer is:
The probability of Ethan, Hannah, or Sophie being drawn is 1/400.

I hope this helps!
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3 years ago
{Thanks for answering my questions!} #thanks
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6=24a so you have to leave the a on one side of the equation. so you divide the 24 on both sides so the a could be by itself and divide 6 by 24. the answer is a=0.25
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3 years ago
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A recipe says to use 4 cups of flour to make 60 cookies. What is the constant of proportionality that relates the number of cook
Sveta_85 [38]

Answer: divide the 60 and the 4 and that's your answer

Step-by-step explanation:

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2 years ago
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

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There all numbers i gues
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