Answer:
See below in bold.
Step-by-step explanation:
1. The sequence is 1000, 2000, 4000, 8000.
2. The common ratio is 2000/1000 = 2.
3. Number of bacteria after 7 hours is 1000(2)^(7- 1)
= 64,000.
4. 1000(2)^(x-1) > 1,000,000
2^x-1 > 1000
x- 1 log 2 > log 10
x- 1 > 9.96
x > 10.96
During the 11th hour.
Answer:
12.4523 kg
Step-by-step explanation:
The variance is found by averaging the square of the deviance (how far a number is from the mean) of each number.
Since we found the average of the deviance, all we have to do now is square that, and divide by the number of subjects.
11.1590² = 124.5232 --> 124.5232/10 = 12.4523 kg
To find how much older Leo is than John, we need to first assign our variables. In this case, let's say that x = Leo, y = Karla, and z = John. Now, let us turn words into numbers.
x = 2y
z = y - 7
Next, we need to create an equation for their combined ages. This is what the equation should look like:
x + y + z = 37
Now, just substitute the expressions we found for x and z. This is what we get:
2y + y + (y - 7) = 37
Solve for y:
2y + y + y - 7 = 37
4y - 7 = 37
4y = 44
y = 11
So now we have the value for y, which is Kayla's age. Therefore, just substitute the value for y back into the equations for x and z.
x = 2(y) => x = 2(11) => x = 22
z = y - 7 => z = 11 - 7 => z = 4
Now that we have the values for x, y, and z, all we need to do now is reassign them back to their respective names. Our final answer will be: John is 18 years older than Leo. The answer to your query would be E) 18. Hope this helps and have a nice day!
N=15/16
hope helps
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