The perimeter of the rectangle below is 104 units. Find the length of side RS.

3) Find the value of FD. bited F 12 12 13x - 16 E 4x+11 D

vlada-n [284]

The Length of FD = 26 cm

According to the given information

FE = FC = 12cm

As FE, FC both are radius of circle

The tangent segments to a circle from a external point are equal

Hence

CD = ED

13x - 16 = 4x + 11

13x - 4x = 11 + 16

9x = 27

x = 27/9

x = 3

CD = 13x - 16

= 13 × 3 - 16

= 23 cm

ED = 4x + 11

= 4 × 3 + 11

= 23 cm

In Triangle FED

FE is perpendicular to ED

According to Pythagoras Theorem

$FD^{2}= FE^{2}+ED^{2}$

= $12^{2}+ 23^{2}$

= 673

FD = 26 cm approx.

The Length of FD = 26 cm

To know more about Pythagoras Theorem

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8 0

1 year ago

98-(5x15)<br>how to answer?

Arte-miy333 [17]

5x15=75 98-75=23 pemdas

7 0

2 years ago

Read 2 more answers

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago

A brace for a shelf has the shape of a right triangle. its hypotenuse is 14 inches long and the two legs are equal in length. ho

maks197457 [2]

To answer this item, we make use of the equation derive from the Pythagorean theorem for right triangles which states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the two shorter sides. If we let x be the measure of both the shorter sides (we call this as legs), we have,
(14 in)² = (x²) + (x²)
Simplifying the equation,
196 in² = 2x²
Divide both sides of the equation by 2,
98 in² = x²
To get the value of x, we get the square root of both sides of the equation,
x = sqrt (98) = 7√2 inches

Hence, the measure of each leg of the right triangle is 7√2 inches or approximately 9.9 inches.

8 0

3 years ago

12. A scientist is observing a family of mice. There are four nice which are reproducing and doubling in number every month. Whi

Margaret [11]

Answer:

?

x = the number of months pass right

3 0

1 year ago