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LiRa [457]
3 years ago
8

Hurry help ASAP!!!!!!!!!!! will give brainliest

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0
The answer is C. 16 since the 3 first surveys medians are 15,16,16. The median of those 3 numbers is 16. So the answer would be C. 16
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Mr. Trager has $500.00 to spend at a bicycle store. All prices listed below include tax. . He buys a new bicycle for $273.98. .
Anon25 [30]

Answer:

2 outfits

Step-by-step explanation:

first you have the total amount of money he has.

next subtract the amount of money he spends on the new bicycle

500-273.98=226.02

next find the total cost of the 3 bicycle reflectors

7.23 times 3 = 21.69

Subtract that total from the remaining amount of money left

226.02 - 21.69 = 204.33

Then subtract the helmet from the remaining money

204.33 - 42.36 = 161.97

now divide the remaining money by 78.12 to find out how many outfits he can buy

161.97 / 78.12 = around 2.07

So the answer is he can only buy 2 outfits with the remaining money

(you can not buy 2.07 outfits)

hope this helps and was what you were looking for

3 0
3 years ago
2) Find the slope of the line
algol13
Assuming each line goes up by 1. we basically need to find a number that goes by rise/run. to get to the next point we need to go up 1, then to the left by 3. notice the slope is negative so we need to add a negative integer.

answer:

-1/3 (C)

hope this helps! :D
4 0
3 years ago
Read 2 more answers
100 POINTS AND BRAINLIEST IF YOU ANSWER FIRST!
boyakko [2]

Answer:1/3 to the 3rd = 1/9 units

Step-by-step explanation:

a^3 = volume of a cube part 2: 1/2 to the power of 1/2

8 0
2 years ago
If the pictured triangles are congruent what reason can be given
Vaselesa [24]

Answer:

sss(personal opinion)

3 0
3 years ago
Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

\int\limits^y_0 {k(1+2x)} \, =1

where y=20

k=0.0024

Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3

d) Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2}   =198.4-176.89=21.51

8 0
3 years ago
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