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Sunny_sXe [5.5K]
3 years ago
5

What's the circumference of a

Mathematics
1 answer:
Alex3 years ago
6 0

Step-by-step explanation:

radius (r) = 2 inches

circumference (c) = ?

we know

C = 2 πr

= 2 * 3.14 * 2

= 12.56 inches

Hope it will help :)

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25(y+1)-x^2(y+1) i don't know the answer
natita [175]
It seems like you've begun to group and factored out the GCF.

Because the inner binomials (the ones in parentheses) are the same, the next step is to rewrite the equation like so:

(25-x^2)(y+1)

From here, we can further factor (25-x^2) since they are both perfect squares.

(5+x)(5-x)(y+1)

No further terms can be factored so that is the final answer. Hope this helps!
7 0
3 years ago
Solve the following equation.<br> 1/4 (f - 7) = 1 + 3f
Andreyy89

Answer:

f= -1

Hope this helps!

3 0
3 years ago
Read 2 more answers
A line has a slope of One-fourth and passes through point (0.4, negative one-half). What is the value of the y-intercept?
lawyer [7]

Answer:

a. -.06

y=\frac{1}{4}x-0.6  

the y-intercept = -.06

Step-by-step explanation:

by plotting y=\frac{1}{4}x-0.6 on a graph, you can see it intercepts (0.4, - \frac{1}{4})

u sed desmos to find this out

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8 0
3 years ago
Read 2 more answers
Helppppp I’ll mark you brainlist
slava [35]

Answer:

-243

Step-by-step explanation:

Since your finding the 36th term and you know the equation plugin 36(as n) into the arithmetic sequence.

-7(36)+9 = -243

6 0
3 years ago
Please help ill mark brainliest!!!
Bingel [31]

Triangle QST  is similar to triangle PQR

We are given that measure of angle SRP is 90°

Q is the point of the hypotenuse SP

Segment QR is perpendicular to PS and T is a point outside the triangle on the left of s

We need to find which triangle is similar to triangle PQR

So,

Using Angle - Angle - Angle Criterion We can say that

m∠PQR = m∠SQR  (AAA similarity)

m∠SQR=m∠SQT (AAA similarity)

Where m∠Q =90°  in ΔQST and PQR

Therefore ΔQST is similar to ΔPQR

Learn more about similarity of triangles here

brainly.com/question/24184322

#SPJ4

8 0
2 years ago
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