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3 years ago

Here is a diagram of a person standing next to a lorry.

Mathematics

2 answers:

N76 [4]3 years ago

5 0

Answer:

cnhjhjcajcasxhvasbx12445378

Step-by-step explanation:

cefj6aysk

e7dgdg

d6fuwr

f7i

cfvdfe

erma4kov [3.2K]3 years ago

3 0

Answer:

The person is a about 2m

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A student wants to report on the number of meals his friends buy each week. The collected data are below: 4 19 3 3 2 3 2 4 Which

lbvjy [14]

median;

i tried mean 3, and mean 5 is wrong for sure, meaning it is median

explanation

arranged least to greatest

2, 2, 3, 3, 3, 4, 4, 19 (8 numbers)

3+3/2=3

median=3

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x ≤ 3

Step-by-step explanation:

4x ≤ 12

divide each side by 4

x ≤ 3

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in mrs marshall's classroom 6/7 of the students play sports. of the students who play sports, 4/5 also play an instrument. if th

yanalaym [24]

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3 years ago

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F(x)=x-1/x^2-x-6 which is the graph of

hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

As you have not added the graph, so I will be solving the function for a graph.

Given the function

$f\left(x\right)=x-\frac{1}{x^2}-x-6$

$x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:$

$\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0$

$-\frac{1}{x^2}-6=0$

$-1-6x^2=0$

$\mathrm{No\:Solution\:for}\:x\in \mathbb{R}$

$\mathrm{No\:x-axis\:interception\:points}$

$y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:$

$y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

$\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}$

$\mathrm{No\:y-axis\:interception\:point}$

$\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6$

$\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)$

The graph is attached below.

5 0

3 years ago