Question

Determine the equation of the graph and select the correct answer below.

Answer 1

Answer:

The standard equation of parabola:

$y =a(x-h)^2+k$             ....[1]

where, vertex = (h, k) and a is any constant value.

As per the statement:

In the given graph of parabola:

Vertex of parabola = (-2, -4)

⇒h = -2 and k= -4

Substitute in [1] we have;

$y =a(x+2)^2-4$               ....[2]

Since, the graph of parabola cuts at y-axis at (0, -8)

Substitute this point in [2] to solve for a, we have;'

$-8=a(0+2)^2-4$

⇒$-8=a(2)^2-4$

Add 4 to both sides we have;

$-4=a(2)^2$

⇒$-4=4a$

Divide both sides by 4 we have;

a = -1

then, the equation become:

$y =-1(x+2)^2-4$

Therefore, the equation of the graph is, $y =-(x+2)^2-4$

Answer 2

F(x+2)= -x^2 -4. Use basic transformations