Using product rule;
f(x)=(1+6x²)(x-x²)
f'(x)=(12x)(x-x²) + (1-2x)(1+6x²) = 12x² -12x³ +1 +6x² -2x -12x³ = -24x³ +18x² -2x +1
Solving the bracket first;
f(x)=(1+6x²)(x-x²) = x -x² +6x³ -6x^4
f'(x)= 1 -2x +18x² -24x³ = -24x³ +18x² -2x +1
Answer:
No
Step-by-step explanation:
The Side-Angle-Side rule of congruence
two triangles are congruent if two sides and one included angle in a given triangle are equal to the corresponding two sides and one included angle in another triangle.
Hey there,
<u>What </u><u>are </u><u>the </u><u>values </u><u>of </u><u>a,</u><u> </u><u>b </u><u>and </u><u>c?</u>
5x² + 2 = 4x
5x² + 2 - 4x = 4x - 4x
5x² - 4x+ 2 = 0
<em>Quadratic </em><em>général </em><em>e</em><em>quation</em><em>:</em>
ax² + bx + c = 0
I hope this helps ✅(◠‿◕)
Answer: A
Step-by-step explanation:
3x² - 10x + 5 = 0
a = 3 b = -10 c = 5
Δ = b²- 4ac = 100 - 4.3.5 = 40 > 0 => have 2 solutions
=> x = 
or x = 
Answer:
x=ln(61)/ln(4)
Step-by-step explanation:
4^x+3=64
4^x=64-3
4^x=61
x=ln(61)/ln(4)
