All categories

3 years ago

Can someone help me solve number 1-8? Plzzz I really need help!!!!!!!

Mathematics

1 answer:

Nostrana [21]3 years ago

4 0

Answer:

1.) x = 1

2.) x = -30

3.) x = -2

4.) x = 15

Sorry I have to work on other stuff but I did half of them for ya

Step-by-step explanation:

You might be interested in

Based on this description, what conclusion did outsiders most likely draw about West African leaders after meeting Mansa Musa?

katrin2010 [14]

Answer:

Step-by-step explanation:

8 0

2 years ago

1) f(x)=(x - 3)(x - 5)

NemiM [27]

Answer:

Step-by-step explanation:

f(x)= (x - 3)(x - 5)

f(x) = x^2 - 5x - 3x + 15

f(x) = x^2 - 8x + 15

Answer is A

7 0

3 years ago

55x^ 2 + 62y^2 + 38 − 63X^ 2 + 8<br> combine like terms<br> WILL GIVE BRAINLIEST

Butoxors [25]

Answer:

− 8 x^ 2 + 62 y ^2 + 46

Step-by-step explanation:

heheheh I do math lol

3 0

3 years ago

Read 2 more answers

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

3 years ago

Read 2 more answers

1. One skater paid $108.00 for

aliya0001 [1]

Answer:

each jewel was 3 $

Step-by-step explanation:

divide 108.00/36= 3

5 0

3 years ago

Read 2 more answers