All categories

3 years ago

Solve the inequality for x. x-c/d > y (for d > 0)

Mathematics

1 answer:

babymother [125]3 years ago

6 0

Answer:

$x>y+\dfrac{c}{d}$

Step-by-step explanation:

The given inequality is :

$x-\dfrac{c}{d}>y$

We need to solve the inequality for x.

Adding $\dfrac{c}{d}$ to the both sides of the inequality.

$x-\dfrac{c}{d}+\dfrac{c}{d}>y+\dfrac{c}{d}\\\\x>y+\dfrac{c}{d}$

Hence, the solution the inequality is $x>y+\dfrac{c}{d}$ .

You might be interested in

FASTTTTT PLEASEEEEEEEE

Bumek [7]

Answer:

i dont think anyone can see it i cant

Step-by-step explanation:

6 0

3 years ago

A train travels 51 kilometers in 4 hours, and then 69 kilometers in 5 hours. What is its average speed?

nata0808 [166]

add the mileage 51+69 = 120 km

add the times 4+5=9 hours

now divide the two

120/9 = 13.3 km per hour average speed

6 0

4 years ago

If you are given the surface area of a square pyramid and the area of the base, how could you calculate the area of each side of

stiv31 [10]

Answer:

you need to divide the surface are and the base and you should get the number of each lateral face

Step-by-step explanation:

but you do need to tell me the numbers so do that in the comments

8 0

3 years ago

A scientist listed the volumes, in milliliters, of some liquids used in an experiment.

Aloiza [94]

Answer:

B) 1.078 < 1.23 (T)

Step-by-step explanation:

A) 1.23 < 1.203 (F)

B) 1.078 < 1.23 (T)

C) 1.17 > 1.203 (F)

D) 1.078 > 1.17 (F)

4 0

3 years ago

Read 2 more answers

Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample

adelina 88 [10]

Answer:

$\sigma = 12.5$ ---- sample standard deviation

$\sigma^2 = 157.2$ ---- sample variance

Step-by-step explanation:

Solving (a): The sample variance

First, we calculate the midpoint of each class (this is the average of the limits)

So, we have:

$x_1 = \frac{56 + 64}{2} = 60$

$x_2 = \frac{65 + 73}{2} = 69$

And so on

So, the table becomes:

$\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}$

Calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}$

$\bar x = \frac{4191}{55}$

$\bar x = 76.2$

The variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}$

$\sigma^2 = \frac{8488.8}{54}$

$\sigma^2 = 157.2$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2$

$\sigma = \sqrt{157.2$

$\sigma = 12.5$

Solving (b): The sample variance

In (a), we calculate the sample variance to be:

$\sigma^2 = 157.2$

6 0

3 years ago