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larisa86 [58]
3 years ago
8

Find the sum of all 11 terms of an AP whose middlemost terms is 30?

Mathematics
1 answer:
Bond [772]3 years ago
6 0

Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.

Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.

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Step-by-step explanation:

The Normal distribution is a continuous probability distribution with possible values all the reals. Some properties of this distribution are:

Is symmetrical and bell shaped no matter the parameters used. Usually if X is a random variable normally distributed we write this like that:

X \sim N(\mu , \sigma)

The two parameters are:

\mu who represent the mean and is on the center of the distribution

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Example: Usually this distribution is used to model almost all the practical things in the life one of the examples is when we can model the scores of a test. Usually the distribution for this variable is normally distributed and we can find quantiles and probabilities associated

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ludmilkaskok [199]
P
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M
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