If you are given the surface area of a square pyramid and the area of the base, how could you calculate the area of each side of
1 answer:
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Answer:
It's probably it
Step-by-step explanation:
A = (-4, -2)
B = (1, 6)
Imagine a new point (C) where they intersect (1, -2)
Now we can form a triangle, the distance between A and B will be the hypotenuse.
h² = 5² + 8²
h² = 25 + 64
h² = 89
h =
h = ~9.43...
h = 9
Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are
The volume of the box is equal to
so
simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A
solve for y
Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x
therefore
The original length was 41 inches and the original width was 16 inches
