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Alina [70]
3 years ago
13

What is the area of a triangle whose sides are 12 6 and 20 meters long

Mathematics
1 answer:
aleksley [76]3 years ago
3 0
38 meters long is the answer
You might be interested in
Q. Find the measure of QR
Andreas93 [3]

Answer: 22

Step-by-step explanation:

Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.

By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.

8 0
3 years ago
Help please!!! Thank you
Anna11 [10]

Answer: ∠ABE=20°

Step-by-step explanation:

∵ AB=BC

∴ ΔABC is a isosceles triangle

∵ ∠A=30

∴ ∠C=30

∵ The interior angle sum of triangle is 180°

∵ ∠A+∠B+∠C=180

    30+∠B+30=180

           ∠B+60=180

                  ∠B=120 (∠ABC)

∵ ∠EBD+∠ABE+∠ABC=linear pair

∴∠EBD+∠ABE+∠ABC=180°

                  4x+2x+120=180

                        6x+120=180

                                6x=60

                                  x=10

∠ABE=2x=2(10)=20°

Hope this helps!! :)

Please let me know if you have any question

6 0
4 years ago
Write the equation of the line shown in point-slope form. (2,1) (3,8)
Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)

(y -8) = \frac{(- 7)}{(-1)}(x-3)

y – 8 = 7(x – 3)

y – 8 = 7x – 21  

7x – y = 21 – 8  

7x – y = 13  

Hence, the line equation that passes through the given points is 7x – y = 13

3 0
4 years ago
Theo can run 1/2 mile in 1/10 hour. If theo continues at this rate how far can he run in a hour?
kirill [66]
1/2 mile x 10 = 5 miles
5 0
3 years ago
 How much fencing is required to enclose a circular garden whose radius is 22 ​m? Use 3.14 for pie
galina1969 [7]

Answer:

138.16 m

Step-by-step explanation:

Circumference=2πr

r=22

C=2·3.14·22

C=138.16


3 0
4 years ago
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