1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nydimaria [60]
3 years ago
9

I'd really appreciate some help on this. Find JL.

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0

Answer:

Dude

the twice of ML is equal to JL....

Now u may ask how can I say this the reason is I used "THE MIDPOINT FORMULAE" do search this concept on utube........

2(5x-16) = 4x+34

So here x is 11

Put the value of it in JL.... so JL is 4*11+34 = 78 units......

You might be interested in
The latest online craze is a new game, Khan on Seven. You get 100 points for playing the game. In addition, you get 50 points fo
Anettt [7]
The inequality would be 50w + 100 >_ 18,000 ( the _ goes under the > but I cannot do that on my phone )
7 0
3 years ago
Read 2 more answers
Help needed with these for problems
Tatiana [17]
I can't read the first one and I also don't know
4 0
3 years ago
So..i can't do the limit..can you please help me...i am sure that a have to apply the test for divergence.
stich3 [128]
Holy moleey what are you learning
7 0
3 years ago
I don't know how do do it can u help me ​
Blizzard [7]

Answer:

The second regon

Step-by-step explanation:

4 0
3 years ago
A researcher wants to see if birds that build larger nests lay larger eggs. He selects two random samples of nests: one of small
True [87]

Answer:

95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.

Step-by-step explanation:

Confidence interval is given by mean +/- margin of error (E)

Eggs from small nest

Sample size (n1) = 60

Mean = 37.2

Sample variance = 24.7

Eggs from large nest

Sample size (n2) = 159

Mean = 35.6

Sample variance = 39

Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11

Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93

Difference in mean = 37.2 - 35.6 = 1.6

Degree of freedom = n1+n2 - 2 = 60+159-2 = 217

Confidence level = 95%

Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132

E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79

Lower limit = mean - E = 1.6 - 0.79 = 0.81

Upper limit = mean + E = 1.6 + 0.79 = 2.39

95% confidence interval for the difference in average mass is (0.81, 2.39)

3 0
3 years ago
Other questions:
  • The volumes of two similar figures are 27 mm^3 and 1331 mm^3. If the surface area of the smaller figure is 18 mm^2, what is the
    13·1 answer
  • a person invests 9000 dollars in the back. The back pats 4.75% interest compounded quarterly. To the tenth of a year, how long m
    11·1 answer
  • 4 less than the quotient of a number x and 5
    8·1 answer
  • Solve 2y=8x 6 show it on graph
    9·1 answer
  • Solve |3x + 3|= 27
    7·1 answer
  • It is urgent.so anyone solve this
    10·2 answers
  • If the discriminant is negative then the quadratic has
    11·1 answer
  • I need help ASAP<br> please and thank you
    15·1 answer
  • 7 friends share 840g of chocolate equally between them.
    8·2 answers
  • Mr. Jones bought a cloth of length 3890 cm. How much is the length in m and cm?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!