Answer:
Yes, Rolle's theorem can be applied
There is only one value of c such that f'(c) = 0, and this is c = 1.5 (or 3/2 in fraction form)
Step-by-step explanation:
Yes, Rolle's theorem can be applied on this function because the function is continuous in the closed interval (it is a polynomial function) and differentiable in the open interval, and f(a) = f(b) given that:
Then there must be a c in the open interval for which f'(c) =0
In order to find "c", we derive the function and evaluate it at "c", making the derivative equal zero, to solve for c:
There is a unique answer for c, and that is c = 1.5
Answer: D.
Step-by-step explanation:
For an absolute value function, the vertex of 
is defined as the point (-h, k) for the coordinate (x, y).
When x is equal to negative h, the value for x and value for h effectively cancel out, and only the positive k remains, hence the vertex being (-h, k).
The function given has a vertex at (2, 3). We know that the vertex of an absolute function is (-h, k), so h must equal -2 and k must equal 3.
The equation:
Use the distance formula: D=sqrt((x2-x1)^2+(y2-y1)^2)
Plug in:
D=sqrt((9-8)^2+(-1-2)^2)
D=sqrt(1^2+(-3)^2)
D=sqrt(1+9)
D=sqrt(10)
So the distance is about 3.16 units
Hope this helped!
Answer:
c. 95 beetles
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
the answer is 15. hope this helps
