Graphing the system of equations is shown in figure attached.
Solution set is (2,-4). The lines will intersect at (2,-4)
Step-by-step explanation:
We need to graph the system of equations. 
First we will find value of x and y
Let:

Add eq(1) and eq(2)

Putting value of x in eq(1) and finding y

So, y=-4
Graphing the system of equations is shown in figure attached.
Solution set is (2,-4). The lines will intersect at (2,-4)
Keywords: System of equations
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Answer:
I think it's true
Step-by-step explanation:
Answer:
1/3 is the simplified form for given expression.
Step-by-step explanation:
Given that:
=![\sqrt[-3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B-3%5D%7B27%7D)
By simplifying:
Radical sign will be removed as follows:
= 
For removing the "-" sign from power, base will be inverted:
= 
27 can also be written as 3 * 3 * 3 = 3^3
So,
= 
= 
By simplifying we get:
= 1/3
i hope it will help you!
Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable <em>X</em> can be defined as the pregnancy length in days.
Then, from the provided information
.
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ <em>z</em> = 1.23
Compute the value of <em>x</em> as follows:

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ <em>z</em> = -1.645
Compute the value of <em>x</em> as follows:

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.