Some help me again lol please no links please

Pls help again thanks

Ksju [112]

Answer:

d.156.

x+24=180 ( being staright angle)

7 0

3 years ago

Translate “the sum of x and one-half of x” into mathematical expression

Aleks [24]

Answer:

X+ 0.5X or 1.5X

Step-by-step explanation:

the sum means that it want an addition problem. and so it is saying X + 1/2 (0.5)X which gives you 1.5X or you can leave it has X+0.5X

5 0

3 years ago

Given |u| = 10 at ∠135° and |v| = 5 at ∠30°, what expression can be used to find |u + v|?

astraxan [27]

Answer:

B, $10^{2} + 5^{2}- 2(10)(5)cos(75)$

Step-by-step explanation:

Using the law of cosines, which is $c^{2}=a^{2}+b^{2}-2ab cos(C)$ , you can simply insert all the values.

c=|u+v|

a= r value of u (10)

b= r value of v (5)

To find C, you simply have to subtract v from u, and then subtract that number from 180 to find the reference angle.

I.E.: ∠135 - ∠30 = ∠105 ↔ 180 - 105 = 75 = C

so, the completed equation would be 10^{2} + 5^{2}- 2(10)(5)cos(75)

5 0

3 years ago

Read 2 more answers

At the city museumy child admission is and admission is $9.30. On Monday four times as many adult tickets as child tickets were

Scilla [17]

Question:

At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?

Answer:

36 child tickets were sold

Solution:

Given that,

Cost of 1 child admission = $ 5.80

Cost of 1 adult admission = $ 9.30

Let "c" be the number of child tickets sold

Let "a" be the number of adult tickets sold

On Monday, four times as many adult tickets as child tickets were sold

Number of adult tickets sold = four times the number of child tickets

Number of adult tickets sold = 4(number of child tickets sold)

a = 4c ----- eq 1

They were sold for a total sales of $ 1548.00

number of child tickets sold x Cost of 1 child admission + number of adult tickets sold x Cost of 1 adult admission = 1548.00

$c \times 5.80 + a \times 9.30 = 1548$

5.8c + 9.3a = 1548 ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

Substitute eqn 1 in eqn 2

5.8c + 9.3(4c) = 1548

5.8c + 37.2c = 1548

43c = 1548

c = 36

Thus 36 child tickets were sold that day

6 0

3 years ago

Suppose that a committee is studying whether or not there is waste of time in our judicial system. It is interested in the mean

Svetach [21]

Answer:

a) Option 1 is correct.

The Student's t-distribution for 80 degrees of freedom should be used because we do not know the population standard deviation.

b) Confidence interval for the population is given as (6.27, 7.73)

c) Option 4 is correct.

We are 95% confident that the true population mean wait time at the courthouse lies within this interval.

Step-by-step explanation:

Sample Mean = 7 hours

Sample standard deviation = 3.3 hours.

Sample size = 81

To construct the confidence interval for the population mean time wasted,

Since there's no information on the population standard deviation, the t-distribution will be used.

The t-distribution is used when there is no information on the population mean or standard deviation. We then assume that the sample standard deviation is a good estimate of the population standard deviation. And that the sample mean too, is a good estimate of the population mean.

The degree of freedom for t-distribution is given as (n-1).

df = 81 - 1 = 80

Hence, the correct answer for (a) is Option 1.

The Student's t-distribution for 80 degrees of freedom should be used because we do not know the population standard deviation.

b) To construct the 95% confidence interval for the population mean time wasted

Confidence interval = (Mean) ± (Margin of error)

Mean = 7 hours

Margin of Error = (Critical value) × (Standard error)

Critical value = t-score for a significance level of (0.05/2) and a degree of freedom of 80.

Note that the significance level.is obtained by subtracting the confidence interval from 100% and dividing it by 2 to accommodate significance at the start and end of the distribution.

So, t (0.025, 80) = 1.990 (obtained from literature)

Standard error = (σ/√n) = (3.3/√81) = 0.3667

Margin of Error = (Critical value) × (Standard error)

= 1.990 × 0.3667 = 0.7297

Confidence interval = (Mean) ± (Margin of error)

= 7 ± 0.7297 = (6.2703, 7.7297) ≈ (6.27, 7.73)

c) The interpretation for confidence interval is that the range given by the confidence interval is understood to contain the true mean required (in this case, the population mean), with a certain confidence level.

So, it is clear that the right answer is "we are 95% confident that the true population mean wait time at the courthouse lies within this interval".

Hope this Helps!!!!

5 0

3 years ago