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wlad13 [49]
1 year ago
14

Select the ordered pairs that represent solutions to the system of inequalities.Select all that applyAnswer choices:(-6, 3)(-3,

3)(-5, 0)(-4, 2)(0,0)(-6, 6)(-3, -6)(-4.0)

Mathematics
1 answer:
Nadya [2.5K]1 year ago
5 0

We can verify this with the graph

(-6, 3) NO

(-3, 3) NO

(-5, 0) NO

(-4, 2) YES

(0,0) NO

(-6, 6) YES

(-3, -6) NO

(-4.0) YES

the area where the solutions are in the yellow area

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7 0
3 years ago
Read 2 more answers
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
Need help on these two please
fredd [130]
Your rays are
F
E

Segments
DF
DE
EF
8 0
3 years ago
IS MY ANSWER CORRECT?!<br><br>-- I'm thinking it's 36 If its wrong. --
balu736 [363]

Answer:

you have the right answer

Step-by-step explanation:

you can check by multiplying 27 and 12. then multiply 20.25 with 16 and both times you will get 324

3 0
4 years ago
Read 2 more answers
(A) find F(x) for the indicated values of x, if possible
dem82 [27]

Answer:

A) The indicated values of F(x) for x=-3 and x=5 are F(-3)=-27  and F(5)=125

B) The domain of f is the set of all real numbers

Step-by-step explanation:

Given that the function F is defined by

F(x)=x^3 for x=-3,5

A) To find F(x) for the indicated values of x :

Given F(x)=x^3 for x=-3,5

  • Put x=-3 in the given function

F(-3)=(-3)^3

=(-3)\times (-3)\times (-3)

=-27

Therefore F(-3)=-27

  • Put x=5 in the given function

F(5)=(5)^3

=(5)\times (5)\times (5)

=125

Therefore F(5)=125

The indicated values of F(x) for x=-3 and x=5 are F(-3)=-27  and F(5)=125

B) To find the domain of f :

The domain of the f in the given expression is the set of all real numbers except where the expression x^3 is undefined. In this case, there is no real number that makes the expression undefined.

The domain of f is the set of all real numbers

8 0
3 years ago
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