How do i solve 2× - 4×
1 answer:
You might be interested in
Answer:
Part 1) The quadratic equation has zero real solutions
Part 2) The solutions are
and
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form is equal to
in this problem we have
so
The discriminant is equal to
If D=0 -----> the quadratic equation has only one real solution
If D>0 -----> the quadratic equation has two real solutions
If D<0 -----> the quadratic equation has two complex solutions
<em>Find the value of D</em>
-----> the quadratic equation has two complex solutions
<em>Find out the solutions</em>
substitute the values of a,b and c in the formula
Remember that
Answer:
Step-by-step explanation:
Hello!
<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected days </em>
<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>
<em>Days 18 27 31 40 56 55 23 </em>
<em>Use it to answer questions 13 and 14. </em>
<em>13. What is the approximate value for the modal daily sales? </em>
To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)
The modal interval is [3.1-3.5]
Now using the following formula you can calculate the Mode:
Li= Lower limit of the modal interval.
c= amplitude of modal interval.
fmax: absolute frequency of modal interval.
fprev: absolute frequency of the previous interval to the modal interval.
fpost: absolute frequency of the posterior interval to the modal interval.
<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>
Of all options the closest one to the estimated mode is A.
<em>14. The approximate median daily sales is … </em>
To calculate the median you have to identify its position first:
For even samples: PosMe= n/2= 250/2= 125
Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.
F(1)= 18
F(2)= 18+27= 45
F(3)= 45 + 31= 76
F(4)= 76 + 40= 116
F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]
Li: Lower limit of the median interval.
c: Amplitude of the interval
PosMe: position of the median
F(i-1)= accumulated absolute frequency until the previous interval
fi= simple absolute frequency of the median interval.
<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>
Of all options the closest one to the estimated mode is C.
Answer:
Area of triangle = 15 square units
Step-by-step explanation:
We need to find area of the triangle, given the vertices:
A=(4,0)
B=(1,5)
C=(7,5)
The formula used is:
We have:
Putting values and finding area
We will be ignoring negative sign, because area of triangle is positive.
So, Area of triangle = 15