Answer:
P(I⋂D)
Step-by-step explanation:
The symbolic way to represent the probability of a true positive is P(I⋂D).
We know that I stands for Infected, U stands for Uninfected, D for Infection detected, N for infection no detected.
Then, a true positive will be given by the intersection of Infected and Infection Detected.
Answer:
Option B
Step-by-step explanation:
Given the following question:

In order to find the answer, we simply apply the exponent rule and add the exponents.



The answer is option B or "5^6."
Hope this helps.
The equation for the direct variation is y= kx (where k is contant of variation.)
This equation represent that if x will increase then y will also increase because it's k times x.
Where the equation for indirect variation is 
By this equation if x will increase then y will decrease and vice versa.
The given data is :
x: 2 4 8 12
y: 4 2 1 2/3
Notice as x is increasing then y is decreasing. Like x has increased from 2 to 4 then y is decresing from 4 to 2 and so on.
So, the given data represent an indirect variation.
Answer:
The expected value for a student to spend on lunch each day = $5.18
Step-by-step explanation:
Given the data:
Number of students______$ spent
2 students______________$10
1 student________________$8
12 students______________$6
23 students______________$5
8 students_______________$4
4 students_______________$3
Sample size, n = 50.
Let's first find the value on each amount spent with the formula:
Therefore,
For $10:
For $8:
l
For $6:
For $5:
For $4:
For $3:
To find the expected value a student spends on lunch each day, let's add all the values together.
Expected value =
$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24
= $5.18
Therefore, the expected value for a student to spend on lunch each day is $5.18
Answer:
The line passes through (4, -7) and (5, -10).
Step-by-step explanation:
When x = 4, y = 5 - 3(4), or 5 - 12, or -7. Thus the point (4, -7) lies on the graph. Similarly y = 5 - 3(5) = -10 when x = 5. Thus, the line also goes through (5, -10). Plot these two points and draw a line through them. Doing this will result in the desired graph.