Answer:
No, the smallest ratio between a hypotenuse and a leg is in the 45/45/90 special case. In this case, the ratio between the hypotenuse and either legs is
√2:1
If the leg is 10 inches long, the smallest the hypotenuse can be is 10√2.
Use the quadratic formula -b+/-√b^2 -4(ac) / 2a
-4 +/- √(4^2 - 4(1*10) / (2*1)
X = -2 +/- i√6
Answer:
Step-by-step explanation:
circle A is
x²+y²+6x-4y-12=0
x²+6x +y²-4y =12
think (a+b)² = a²+2ab+b² we have a=x, b= 3
and (a-b)² = a²-2ab+b² so we have a=y, b=2
x²+6x +9 +y²-4y+4 = 12-9-4
(x+3)² +(y-2)²= -1
compare to the general equation of a circle (x-h)²+(y-k)² =r²
the center is at (-3,2) and the radius is √-1 =i
Circle B has center (0, -4) and radius 3 so the equation is
(x-0)²+(y-(-4))² =3²
x² +(y+4)² = 9
point (√8, -3) is on the circle if it verifies the equation
√8² +(-3+4)² = 9
8+1 =9 true so the point is on the circle
Circle A and circle B are not similar because they do not have the same center and radius
Answer:
0.90
Step-by-step explanation:
I’m doing the unit test
