Answer:
see below
Step-by-step explanation:
The applicable rules of exponents are ...
- (a^b)(a^c) = a^(b+c)
- a^(-b) = 1/a^b
Using these to simplify your expression, you get ...
Franco:
3x+2y=19
Caryl:
2x+4y=24
now use elimination
-2(3x+2y=19)
1(2x+4y=24)
=
-6x-4y=-38
2x+4y=24
add them together
which equals -4x=-14
divide both sides by -4
-4x/-4=-14/-4
x=7/2
we found x, so we subsitute it into the the original equation
3x+2y=19
3(7/2)2y=19
2y+21/2=19
-21/2 -21/2
2y=17/2
divide by 2 on both sides
2y/2= 17/2/2
y=17/4
so x= 7/2 and y= 17/4
Answer:
Step-by-step explanation:
Given both numbers are greater than 6
Their HCF is 6
Their LCM is 60
The product of the HCF and LCM of two numbers is the same as the product of the numbers themselves.
Let us say those number are and
So, the product of those number is
Let us factorize
It is given that number should be greater than 6
The possible pairs of number are
But only has LCM as 60.
So those numbers are
Im guessing the answer is 21 but then again don't trust me and use an algebraic calculator
Answer:
$7499.82
Step-by-step explanation:
We have been given that a person places $6340 in an investment account earning an annual rate of 8.4%, compounded continuously. We are asked to find amount of money in the account after 2 years.
We will use continuous compounding formula to solve our given problem as:
, where
A = Final amount after t years,
P = Principal initially invested,
e = base of a natural logarithm,
r = Rate of interest in decimal form.
Upon substituting our given values in above formula, we will get:
Upon rounding to nearest cent, we will get:
Therefore, an amount of $7499.82 will be in account after 2 years.