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3 years ago

Help me please its easy

Mathematics

1 answer:

Helga [31]3 years ago

8 0

Answer:

So jane can fill 3 cases cause there are 3 beverages and she will have 0 bottles left

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Factorise the following.

Alika [10]

Answer:

x⁴ - y⁴= (x²)²- (y²)² = (x² + y²)(x²- y²) = (x²+y²)(x)²-(y)²=(x²+y²)(x+y)(x-y)

49x²-16/25= (7x)²- (4/5)²=(7x+4/5)(7x-4/5)

3 0

3 years ago

Read 2 more answers

Find the value of x such that 3^(x^2)/ (3^(2x))=27

cestrela7 [59]

This is how this one is done. I'm assuming by this type of a problem that you are in logs in math since you need to rules of logs to solve it. First things first...laws of exponents when the bases are like. Our base is a 3. Here's the problem written out: $\frac{3^ x^{2} }{3 ^{2x} } =27$ . The rules for exponents when dividing like bases is that you subtract the exponents. So we will do that: $3^{x^2-2x} =27$ . Since we are solving for x we need to find a way to get it down from its exponential position. We do that by takking the log of both sides. $log 3^{x^2-2x}=log27$ . Another rule of logs, the power rule, is that once we take the log of a base with an exponent, we can move the exponent down in front, like this: $x^2-2x[log(3)]=log27$ . Now we will divide both sides by log(3) to get $x^2-2x= \frac{log(27)}{log(3)}$ . We do that math on the right side on our calculator to get $x^2-2x=3$ . Now this is something we can handle. We have a second degree polynomial that we have to factor for x. Do that by moving the 3 over by subtraction. $x^2-2x-3=0$ . Factoring that you have that x = 3 and x = -1. There you go!

4 0

3 years ago

Please help with dilation(please click and help me answer)

bekas [8.4K]

P is at 0,-1
Q is at 2,-1
R is at 2, -2
S is at 0, -2

8 0

3 years ago

in 2014 the attendance at jefferson schools fall festival was 600 in 2015 the attendance was 575 what was the percent change in

pantera1 [17]

$600 - 575 = 25$

$\dfrac{25}{600} \times 100\% = 4.17\%$

Answer : 4.17%

Hope this helps. - M

8 0

3 years ago

A business journal investigation of the performance and timing of corporate acquisitions discovered that in a random sample of 2

ANTONII [103]

Answer:

Step-by-step explanation:

Using the one sample proportion test:

z = (p-P) / √{P (1-P)/n}

Where p = 709/2640= 0.27, P = 0.29, n= 2640

Thus z = (0.27-0.29) / √{0.29 (1-0.29) / 2640}

z = (-0.02) / √{0.29(0.71) /2640}

z = (-0.02) / √0.00007799

z = (0.02) / 0.0088

z = 2.27

To be able to draw a conclusion, lets find the p value at the 0.1 level of significant: p value is 0.2327. The result is significant as the p value is greater than 0.1 thus we will fail to reject the null and conclude that there is not enough statistical evidence to prove that the true percentage of all firms that announced one or more acquisitions during the year 2000 is less than 29%

8 0

3 years ago