Answer:
Given : BRDG is a kite that is inscribed in a circle,
With BR = RD and BG = DG
To prove : RG is a diameter
Proof:
Since, RG is the major diagonal of the kite BRDG,
By the property of kite,
∠ RBG = ∠ RDG
Also, BRDG is a cyclic quadrilateral,
Therefore, By the property of cyclic quadrilateral,
∠ RBG + ∠ RDG = 180°
⇒ ∠ RBG + ∠ RBG = 180°
⇒ 2∠ RBG = 180°
⇒ ∠ RBG = 90°
⇒ ∠ RDG = 90°
Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.
⇒ RG is the diameter of the circle.
Hence, proved.
Quite a broad question. 10/2 you divide by 2 which equals 5. Is that your question?
Answer:
I'm confused
Step-by-step explanation:
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Answer:
38
Step-by-step explanation:
Notice that the first triangle is an isosceles triangle, meaning that the base angles are equivalent. Since one angle is 62, we know that the other is 62 as well, which makes 124. This means that angle 2 is 56 degrees. Since 2 and 3 are on the same 'line', they both add up to 180. If 2 is 56, then angle 3 is 124. So the three angles inside the triangle are 124, 18, and x. So, 124+18=142. 180-142= 38
