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3 years ago

14

Not sure how to do these. i need help with 13! needing it to be reduced just like y should be 8

2 answers:

Delicious77 [7]3 years ago

8 0

Answer:

I'm not sure 710

Step-by-step explanation:

I'm not sure

Kazeer [188]3 years ago

6 0

Answer:

#14

y=5

x=14

Step-by-step explanation:

I did 14 for you

the two expressions with x equal each other since they are on the same side of their line, similar to eachother. Then plug in x into one of those expressions and do 180- your answer to get the angle for one of the y expressions since its on the other side of the line. both angles have to add up to 180.

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It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the

son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that $p = 0.5$

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039$

$P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313$

$P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094$

$P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188$

$P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734$

$P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556$

85.56% probability that less than 6 of them have a high school diploma

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3 years ago

T(a+b)=r solve for a I need help due tomorrow

tigry1 [53]

Divide both sides by <span>t
</span>
<span>a+b=r/t

</span>Subtract b <span>from both sides
</span>
a<span>=r/t-b = Solution </span>

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frosja888 [35]

ur answer is 5 and -5

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bagirrra123 [75]

Answer:

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Tasya [4]

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