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algol13
3 years ago
6

Please help me i need help

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer:

H

E

A

R

T

S

Step-by-step explanation:

easy

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Find the value of variable x. If your answer is not an integer, write it in simplest radical form with the denominator rationali
Otrada [13]

Answer:

the answer is 7

Step-by-step explanation:

angle 30°

x=14/2

x=7

8 0
3 years ago
Solve w^3 - 9w = 0 by factoring
madam [21]

Answer:

w = 0 , -3 , 3

Step-by-step explanation:

w³ - 9w = 0

w(w² - 9) = 0

w(w² - 3²) = 0

w(w+3)(w-3) = 0            {a² - b² = (a + b)(a - b) }

w = 0   ;  w + 3 = 0                ; w - 3 = 0

                     w = -3              ;        w = 3

w = 0 , -3 , 3

5 0
3 years ago
s Chegg uppose you have purchased a filling machine for candy bags that is supposed to fill each bag with 16 oz of candy. Assume
Novosadov [1.4K]

Answer:

it 68.9

Step-by-step explanation:

because u add all that

6 0
2 years ago
Brainliest for the first solution
mr Goodwill [35]

Q1  Solution:

x = 3 or x = -1

Step-by-step explanation:

x²-2x-3 = 0

In order to solve the quadratic equation by factoring, we have to determine two numbers whose sum is -2 and their product -3. By trial and error the two numbers are found to be; -3 and 1. The next step is to split the middle term by substituting it with the above two numbers found;

x²+x-3x-3  =  0

x(x+1)-3(x+1)  = 0

(x-3)(x+1) = 0

Finally we apply the zero Product Property :

If ab = 0 then a  = 0 or b  = 0

This implies;

x-3= 0 or x+1 = 0

x = 3 or x = -1 are the solutions to x²-2x-3 = 0

Q2  Solution:

x  = -1/2 or x  =  3

Step-by-step explanation:

2x²-5x-3  =0

In order to solve the quadratic equation by factoring, we have to determine two numbers whose sum is -5 and their product 2(-3)=-6. By trial and error the two numbers are found to be; -6 and 1. The next step is to split the middle term by substituting it with the above two numbers found;

2x²-6x+x-3  = 0

2x(x-3)+1(x-3) = 0

(2x+1)(x-3) = 0

2x+1 = 0 or x-3 =  0

2x = -1 or x =  3

x  = -1/2 or x  =  3 are the solutions of the given quadratic equation.

Q3 Soution:

x = 4 or x = 3

Step-by-step explanation:

x²-7x = -12

x²-7x+12 = 0

In order to solve the quadratic equation by factoring, we have to determine two numbers whose sum is -7 and their product 12. By trial and error the two numbers are found to be; -4 and -3. The next step is to split the middle term by substituting it with the above two numbers found;

x²-4x-3x+12 = 0

x(x-4)-3(x-4)  = 0

(x-4)(x-3) = 0

x-4 = 0 or x-3 = 0

x = 4 or x = 3 are the solutions of the given quadratic equation.

Q4:

x = -2/3 or x = 6

Step-by-step explanation:

3x² = 16x+12

3x²-16x-12 = 0

In order to solve the quadratic equation by factoring, we have to determine two numbers whose sum is -16 and their product 3(-12)= -36. By trial and error the two numbers are found to be; -18 and 2. The next step is to split the middle term by substituting it with the above two numbers found;

3x²-18x+2x-12 = 0

3x(x-6)+2(x-6) = 0

(3x+2)(x-6) = 0

3x+2 = 0 or x-6 =0

3x = -2 or x = 6

x = -2/3 or x = 6 are the solutions of the given quadratic equation.

Q5:

x = 6 or x = -4

Step-by-step explanation:

x²-2x-24 = 0

In order to solve the quadratic equation by factoring, we have to determine two numbers whose sum is -2 and their product -24. By trial and error the two numbers are found to be; -6 and 4. The next step is to split the middle term by substituting it with the above two numbers found;

x²-6x+4x-24 = 0

x(x-6)+4(x-6) = 0

(x-6)(x+4) = 0

x-6 = 0 or x+4 = 0

x = 6 or x = -4 are the solutions to the given quadratic equation.

Q6:

x  = 4/3 or x  = -1

Step-by-step explanation:

3x² = x+4

3x²-x-4 = 0

In order to solve the quadratic equation by factoring, we have to determine two numbers whose sum is -1 and their product -12. By trial and error the two numbers are found to be; -4 and 3. The next step is to split the middle term by substituting it with the above two numbers found;

3x²-4x+3x-4 = 0

x(3x-4)+1(3x-4)  =0

(3x-4)(x+1) = 0

3x-4 =0 or x+1 =0

3x  = 4 or x = -1

x  = 4/3 or x  = -1 are the solutions to the given quadratic equation.

5 0
2 years ago
Read 2 more answers
Show that 4x - x? – 7 is always<br> negative.<br><br><br><br><br> Help
Verizon [17]

                                          <em>Question No 7</em>

Answer:

Please check the explanation.

Step-by-step explanation:

Show that 4x - x² - 7 is always negative.

Given

4x - x² - 7

4x - x² - 7 is always negative because:

  • -x²-7 will alwas be negative for all the values of x,
  • The value of  - x² - 7 will always be less than 4x for all the values of x

Hence, 4x - x² - 7 is always negative

For example,

let suppose we enter x = 1

4(1)-1^{2} -7\\=4-1-7\\=4-8\\=-4

let suppose we enter x = -1

4(-1)-(-1)^{2} - 7\\= -4 - 1 - 7\\= -12

6 0
3 years ago
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